Extragere random din foldere multiple

[Nichita]

Problema pe care vreau sa o rezolv este urmatoarea: am 4 foldere, fiecare cu cate 5 elemente. Doresc sa extrag, random, cate un fisier din fiecare folder astfel incat sa generez combinatii multiple (combinari de n luate cate k) de genul:

1-2-3-4 -> folder
1-1-3-4 -> folder
1-1-1-4 -> folder
1-2-1-4 -> folder
1-2-2-4 -> folder
1-2-2-5 -> folder
1-2-5-4 -> folder
1-5-2-4 -> folder
2-2-2-5 -> folder etc. etc.

Exista vreo solutie simpla pentru a rezolva aceasta problema?

[puthre]

Vrei un script sau ce? Ca nu prea se intelege

[Nichita]

Aplicatie sau script. Am testat vreo 2 aplicatii instalabile insa nici una "nu stie" sa faca ce imi doresc.

[puthre]

Aplicatie sau script. Am testat vreo 2 aplicatii instalabile insa nici una "nu stie" sa faca ce imi doresc.

Windows?

[Nichita]

Da.

[haos]

aplicatie sau script. am testat vreo 2 aplicatii instalabile insa nici una "nu stie" sa faca ce imi doresc.

MS-Dos?

[Nichita]

Aplicatiile testate au fost niste programele "random extractor", instalabile, cu interfata etc., nu MS-Dos.

[haos]

Un vbscript sau un bat rezolva, daca nu ai si alte cerinte mai complicate.

[filip.camara]

Nu stiu daca am inteles exact ce vrei.

Aici ai un program care genereaza secvente aleatorii de 4 numere, in gama 1-5 :

4 3 5 2
3 4 1 5
3 4 2 1
2 4 3 5
2 5 3 1
2 4 3 1
5 3 1 4
5 2 4 3


Sursa:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace Nikita
{
    static class RandomHelper
    {
        public static IEnumerable<T> RandomTake<T>(
            this IEnumerable<T> source, Random rng, int count)
        {
            T[] items = source.ToArray();

            count = count < items.Length ? count : items.Length;

            for (int i = items.Length - 1; count-- > 0; i--)
            {
                int p = rng.Next(i + 1);
                yield return items[p];
                items[p] = items[i];
            }
        }
    }

    class Program
    {
        static void Main(string[] args)
        {
            Random rnd = new Random(Environment.TickCount);
            int[] numbers = new int[] { 1, 2, 3, 4, 5};
            bool first = true;
            while (first || Console.ReadKey(true).KeyChar == 'n')
            {
                foreach (int number in numbers.RandomTake(rnd, 4))
                {
                    Console.Write(number + " ");
                }
                first = false;
                Console.WriteLine("\r\n Press 'n' for next, other key to exit");
            }

        }
    }
}

Release.zip

[puthre]

Nu stiu daca am inteles exact ce vrei.

Aici ai un program care genereaza secvente aleatorii de 4 numere, in gama 1-5 :

4 3 5 2
3 4 1 5
3 4 2 1
2 4 3 5
2 5 3 1
2 4 3 1
5 3 1 4
5 2 4 3


Sursa:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace Nikita
{
    static class RandomHelper
    {
        public static IEnumerable<T> RandomTake<T>(
            this IEnumerable<T> source, Random rng, int count)
        {
            T[] items = source.ToArray();

            count = count < items.Length ? count : items.Length;

            for (int i = items.Length - 1; count-- > 0; i--)
            {
                int p = rng.Next(i + 1);
                yield return items[p];
                items[p] = items[i];
            }
        }
    }

    class Program
    {
        static void Main(string[] args)
        {
            Random rnd = new Random(Environment.TickCount);
            int[] numbers = new int[] { 1, 2, 3, 4, 5};
            bool first = true;
            while (first || Console.ReadKey(true).KeyChar == 'n')
            {
                foreach (int number in numbers.RandomTake(rnd, 4))
                {
                    Console.Write(number + " ");
                }
                first = false;
                Console.WriteLine("\r\n Press 'n' for next, other key to exit");
            }

        }
    }
}

Release.zip

Cred ca nichita vorbea de combinari, nu de permutari.