Salutare,
Dupa ce am cumparat acum cateva zile site-ul cerintedesistem.com am observat ca inafara de cateva posturi care aveau seo spam in taguri, restul nu aveau deloc.Cum erau 1400 de posturi varianta manuala nu m-a incantat asa ca am scris un mic script care ar trebui sa mearga pe orice blog wordpress pentru a adauga in cazul meu tag-ul : minimum-system-requirements-$Post_title .Am considerat ca este o idee buna de a castiga vizite pe system requirements jocuxxx .
Codul a fost scris in mare graba si nu foarte frumos , dar in 2s a adaugat 1.400 de taguri, deci este ok.Nu stiu daca exista un plugin de genul, dar poate fi folositor.
Uita-ti cum arata :
Mersi!Cod:define('DB_NAME', 'nume'); /** MySQL database username */ define('DB_USER', 'user'); /** MySQL database password */ define('DB_PASSWORD', 'pass'); /** MySQL hostname */ define('DB_HOST', 'localhost'); /** Conectare la baza de date */ $link_id = mysql_connect (DB_HOST, DB_USER, DB_PASSWORD); if (!$link_id) { $MYSQL_ERRONO = 0; $MYSQL_ERROR = "Unable to conned to host $dbhost"; return 0; } else{ mysql_select_db (DB_NAME, $link_id); } $q ="select ID,post_title,post_name from wp_posts where post_status='publish' and post_type='post'"; $r=mysql_query($q); while ($res = mysql_fetch_assoc($r)){ $tag = "Minimum System Requirements ".$res[post_title]; $slug = "minimum-system-requirements-".$res[post_name]; $object_id = $res[ID]; $q1="insert into wp_terms(name,slug,term_group) values('$tag','$slug',0)"; $r1=mysql_query($q1); $q2="select term_id from wp_terms order by term_id desc limit 1"; $r2=mysql_query($q2); $res1=mysql_fetch_assoc($r2); $term_id=$res1[term_id]; $q3="insert into wp_term_taxonomy(term_id,taxonomy,description,parent,count) values('$term_id','post_tag','',0,1)"; $r3=mysql_query($q3); $q4="select term_taxonomy_id from wp_term_taxonomy order by term_taxonomy_id desc limit 1"; $r4=mysql_query($q4); $res2=mysql_fetch_assoc($r4); $term_taxonomy_id=$res2[term_taxonomy_id]; $q5="insert into wp_term_relationships(object_id,term_taxonomy_id,term_order) values('$object_id','$term_taxonomy_id',0)"; $r5=mysql_query($q5); }




Răspunde cu citat



.Sunt sigur ca solutia ta este mai usoara insa.

